This is not a question, but an answer to a question which was not asked. There is another big thread on this forum on "Fuel Efficiency" where large number of members had posted comments on fuel efficiency of their cars. But looking at some comments, we can clearly identify that, some of the members do not know how to calculate the fuel efficiency correctly. That is why I thought of posting this.
1) Get your car full tanked. Take down the current mileage; say M1.
2) Drive the car until fuel level becomes somewhat low. At least below the quarter of the full level.
3) Re-fuel again to full tank and take down mileage M2 and amount of fuel pumped V2.
4) Now, it is clear that, to move the car from M1 to M2, it has consumed V2 amount of fuel.
Therefore, the fuel efficiency = (M2 - M1) / V2
There may be some fellows who are not familiar with this algebraic formula. For the ease of them, I will try to explain using a numerical example.
1) Get your car full tanked. Take down the current mileage. Suppose it is 76,369km
2) Drive the car until fuel level becomes somewhat low. At least below the quarter of the full level.
3) Re-fuel again to full tank and take down mileage and amount of fuel pumped.
In this time, suppose the mileage is 76,801km and amount of fuel pumped is 45L.
4) Then the distance the vehicle traveled using 45L is 76,801km - 76,369km = 432km.
Therefore, the fuel efficiency is 432km ÷ 45L = 9.6km/L.
This method gives you the average fuel efficiency between these two fillings. But if you need a further accurate figure, you can extend it to multiple number of fillings rather than two. For example if you had five fillings then the formula will be (M5-M1) / (V5+V4+V3+V2)
Please note that the amount of fuel pumped at first filling (V1) is NOT used in the calculation.
I'm going to buy a car in SL for 2 mil while being in Germany. Then I'm going to put up a public raffle draw and pick one lucky winner to gift that car when I have 600 participants registered in the raffle draw. Registration fee for each participant is Rs. 5000/-
Why didnt I think of this before
So for a spirited convo like this old times; ?BYD
My father has gone ninja about getting one, despite being the new hype/fad here these are common across the world and I've seen a few cross 100,000km in Nepal and Australia.
Seal - Looks nice, very premium interior but too low for my applications
Sealion - Very Premium, feels very well built, BUT that 1.5L on that reasonable chunk of car with a measly 18KW battery seems like a recipe for trouble, incase they sink in value at least the fuel economy must justify that (They say it's a BYD engine - though the lore is it is a hyundai engine)
Atto 3 - Most sold from their lot apparently, common af, Seems to be the best bang for buck IMHO, Its electric since BYD is famed for that, Interior is kinda good, the thing is larger than a vezel but not too large like the Sealion, cheap mobility I guess with less things to go wrong
Dolphin, almost a smaller atto and again too car like and not suited for my application.
JK nailed it on the price and distribution but the only guaranteed thing here is the lot are gonna muck up the aftersales. The Kandy center staff behave like the crew from a Govt. post office.
What are your thoughts and opinions? Could this be the next Wagon R or is this a passing fad like the Micros of 2000s-2010s?
I have an empty parking slot at home previously occupied for 6 years by the starlet and 3 months by an AD wagon -what would be a bang-for-the-buck fun shitbox? Preferably auto as I live in a crowded suburb that has sapped the joy of stick shift out of my system.
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Dhaham
Dear Friends
This is not a question, but an answer to a question which was not asked. There is another big thread on this forum on "Fuel Efficiency" where large number of members had posted comments on fuel efficiency of their cars. But looking at some comments, we can clearly identify that, some of the members do not know how to calculate the fuel efficiency correctly. That is why I thought of posting this.
1) Get your car full tanked. Take down the current mileage; say M1.
2) Drive the car until fuel level becomes somewhat low. At least below the quarter of the full level.
3) Re-fuel again to full tank and take down mileage M2 and amount of fuel pumped V2.
4) Now, it is clear that, to move the car from M1 to M2, it has consumed V2 amount of fuel.
Therefore, the fuel efficiency = (M2 - M1) / V2
There may be some fellows who are not familiar with this algebraic formula. For the ease of them, I will try to explain using a numerical example.
1) Get your car full tanked. Take down the current mileage. Suppose it is 76,369km
2) Drive the car until fuel level becomes somewhat low. At least below the quarter of the full level.
3) Re-fuel again to full tank and take down mileage and amount of fuel pumped.
In this time, suppose the mileage is 76,801km and amount of fuel pumped is 45L.
4) Then the distance the vehicle traveled using 45L is 76,801km - 76,369km = 432km.
Therefore, the fuel efficiency is 432km ÷ 45L = 9.6km/L.
This method gives you the average fuel efficiency between these two fillings. But if you need a further accurate figure, you can extend it to multiple number of fillings rather than two. For example if you had five fillings then the formula will be (M5-M1) / (V5+V4+V3+V2)
Please note that the amount of fuel pumped at first filling (V1) is NOT used in the calculation.
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