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Dhaham
Dear Friends
This is not a question, but an answer to a question which was not asked. There is another big thread on this forum on "Fuel Efficiency" where large number of members had posted comments on fuel efficiency of their cars. But looking at some comments, we can clearly identify that, some of the members do not know how to calculate the fuel efficiency correctly. That is why I thought of posting this.
1) Get your car full tanked. Take down the current mileage; say M1.
2) Drive the car until fuel level becomes somewhat low. At least below the quarter of the full level.
3) Refuel again to full tank and take down mileage M2 and amount of fuel pumped V2.
4) Now, it is clear that, to move the car from M1 to M2, it has consumed V2 amount of fuel.
Therefore, the fuel efficiency = (M2  M1) / V2
There may be some fellows who are not familiar with this algebraic formula. For the ease of them, I will try to explain using a numerical example.
1) Get your car full tanked. Take down the current mileage. Suppose it is 76,369km
2) Drive the car until fuel level becomes somewhat low. At least below the quarter of the full level.
3) Refuel again to full tank and take down mileage and amount of fuel pumped.
In this time, suppose the mileage is 76,801km and amount of fuel pumped is 45L.
4) Then the distance the vehicle traveled using 45L is 76,801km  76,369km = 432km.
Therefore, the fuel efficiency is 432km ÷ 45L = 9.6km/L.
This method gives you the average fuel efficiency between these two fillings. But if you need a further accurate figure, you can extend it to multiple number of fillings rather than two. For example if you had five fillings then the formula will be (M5M1) / (V5+V4+V3+V2)
Please note that the amount of fuel pumped at first filling (V1) is NOT used in the calculation.
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